One-variable data: center & spread

These questions ask you to describe a single set of numbers: where its center sits (mean, median, mode) and how spread out it is (range, standard deviation). The most-tested idea is how an outlier pulls the mean but barely moves the median.

Tested on SAT Problem-Solving & Data Analysis

What College Board tests

Computing mean and median (including from a frequency table), reasoning about how a changed or added value affects each, comparing the spread of two data sets, and knowing which measure of center is more resistant to outliers.

Center and spread

Mean
The average: add all values, divide by how many. Sensitive to outliers.
Median
The middle value when sorted (average of the two middle values if the count is even). Resistant to outliers.
Range
Largest minus smallest — a quick measure of spread.
Std. deviation
How far values typically sit from the mean. Larger = more spread. You won't compute it by hand; you'll compare.

An outlier drags the mean toward it but leaves the median almost untouched. When a question adds an extreme value, expect the mean to move and the median to hold.


Four worked examples in SAT format. Read the approach, try it yourself, then tap Show the full solution.

1 · Find the median

A data set is shown: . What is the median of the data set?

Approach The data is already sorted. With six values (an even count), the median is the average of the two middle ones — the 3rd and 4th.

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Answer: B

6 values → the two middle ones are the 3rd and 4th
average them (divide by 2)

Why the other choices are wrong

A  Picks only the 3rd value instead of averaging the middle two.

C  Picks only the 4th value.

D  Computes the mean, not the median.

2 · How an outlier affects center

A data set is . If the value 15 is replaced by 95, how do the mean and median change?

  1. Both the mean and the median increase.
  2. The mean increases; the median stays the same.
  3. The median increases; the mean stays the same.
  4. Neither changes.

Approach Think about what each measure depends on. The mean uses every value, so a huge new number pulls it up. The median depends only on the middle position — check whether replacing the largest value changes what sits in the middle.

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Answer: B

the middle value is still 13 — unchanged
the mean uses every value, including the new 95
up from the original mean of 12.8

Replacing the top value with a far larger one leaves the middle position (13) untouched, so the median holds while the mean jumps.

Why the other choices are wrong

A  The median doesn't increase — 13 is still the middle value.

C  Reverses the two — it's the mean that moves, not the median.

D  The mean clearly changes (12.8 → 28.8).

3 · Mean from a frequency table

The table shows how many households reported each number of pets.

PetsHouseholds
12
23
35

What is the mean number of pets per household?

Approach Don't average 1, 2, 3. Each value is repeated by its frequency. Multiply each pet-count by its number of households, total those, then divide by the total number of households.

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Answer: B

each pet-count × its frequency
total number of pets
total number of households
divide total pets by total households

Why the other choices are wrong

A  Averages 1, 2, 3 directly, ignoring the frequencies.

C  Divides by the number of distinct values (3) instead of total households.

D  Takes the most common value (the mode), not the mean.

4 · Compare spread

Two data sets each have five values with the same mean of 22.
Set P:    Set Q:
Which statement correctly compares the standard deviations?

  1. Set P has the larger standard deviation.
  2. Set Q has the larger standard deviation.
  3. They have equal standard deviations.
  4. Standard deviation can't be compared without computing it exactly.

Approach Standard deviation measures how far values sit from the mean. You don't need to compute it — just see which set's values are bunched near the mean and which are flung far from it.

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Answer: B

values sit within 2 of the mean — tightly bunched
values stretch up to 17 from the mean — widely spread
more spread means a larger standard deviation

Both sets center on 22, but Set Q's values are far from that center while Set P's hug it. Greater distance from the mean means greater standard deviation.

Why the other choices are wrong

A  Reverses it — Set P is the tightly bunched one.

C  Equal means would not force equal spread; their spreads clearly differ.

D  You can compare spread by inspection when one set is plainly more dispersed.


Quick reference

Mean
Sum ÷ count; moves toward outliers.
Median
Middle when sorted; resists outliers.
Freq. table
Multiply value × frequency, then divide by total frequency.
Spread
Farther from the mean → larger standard deviation.
Outlier
Shifts the mean, leaves the median nearly fixed.
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